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Total Addressable Memory

65,536 bytes

Memory (KB)64.0 KB
Memory (MB)0.06 MB
Addressable Locations65,536

Total Addressable Memory vs Address Bus Width (bits)

Formula

Memory Address Space

The address bus width determines how many unique memory locations a processor can access.

Formula

Locations = 2^Address_Bits

Total Memory = Locations x (Data_Bus_Width / 8) bytes

Common Examples

  • 8-bit address: 256 bytes
  • 16-bit address: 64 KB
  • 20-bit address: 1 MB (original PC)
  • 32-bit address: 4 GB
  • 64-bit address: 16 EB (theoretical)
  • Esempio Risolto

    16-bit address bus with 8-bit data bus.

    1. 01Locations: 2^16 = 65,536
    2. 02Bytes per location: 8/8 = 1
    3. 03Total: 65,536 x 1 = 65,536 bytes
    4. 04In KB: 65,536 / 1024 = 64 KB

    Domande Frequenti

    Why can 32-bit systems only address 4 GB?

    2^32 = 4,294,967,296 bytes = 4 GB. Physical Address Extension (PAE) can extend this on some architectures.

    Does data bus width affect address space?

    Not the number of locations, but it affects total bytes. A 16-bit data bus accesses 2 bytes per location.

    What is memory-mapped I/O?

    Hardware registers are placed in the address space, reducing available RAM but simplifying peripheral access.

    Impara

    Ohm's Law Guide

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