Calculadora de Producto Iónico del Agua Gratis
Calcula el producto iónico del agua (Kw) a diferentes temperaturas. A 25°C, Kw = 1.0 x 10⁻¹⁴.
Kw
0.0000
Kw vs Hydrogen Ion Concentration [H⁺]
Fórmula
## Ion Product of Water ### Formula **Kw = [H⁺] × [OH⁻]** At 25°C, Kw = 1.0 × 10⁻¹⁴, meaning: - In pure water, [H⁺] = [OH⁻] = 1.0 × 10⁻⁷ M - If [H⁺] increases, [OH⁻] decreases proportionally - pKw = pH + pOH = 14 at 25°C
Ejemplo Resuelto
Pure water at 25°C has [H⁺] = 1.0 × 10⁻⁷ M and [OH⁻] = 1.0 × 10⁻⁷ M.
- 01Kw = [H⁺] × [OH⁻]
- 02Kw = (1.0 × 10⁻⁷)(1.0 × 10⁻⁷)
- 03Kw = 1.0 × 10⁻¹⁴
- 04pKw = 14.0
Preguntas Frecuentes
What is the ion product of water?
Kw is the equilibrium constant for the autoionization of water: H₂O ⇌ H⁺ + OH⁻. At 25°C it equals 1.0 × 10⁻¹⁴.
Does Kw depend on temperature?
Yes. Kw increases with temperature because autoionization is endothermic. At 60°C, Kw is about 9.6 × 10⁻¹⁴.
Is water neutral at all temperatures?
Pure water is always neutral ([H⁺] = [OH⁻]), but pH of neutral water is only 7.0 at 25°C. At higher temperatures, neutral pH is less than 7.
Aprender