Calcolatore Efficienza Regolatore Switching

Calcola l'efficienza di un regolatore di tensione switching rispetto a quello lineare.

W
x
%
V

Minimum Inverter Rating

1,000 W

DC Input Current (continuous)46.3 A
DC Power Draw556 W

Minimum Inverter Rating vs Continuous Load

Formula

## Inverter Sizing ### Formulas **Inverter Rating = Continuous Load x Surge Multiplier** **DC Current = AC Load / (DC Voltage x Efficiency)** Motors and compressors draw 2-3x surge at startup. Size the inverter for the surge, not just continuous load.

Esempio Risolto

500 W continuous load, 2x surge, 90% efficient inverter on 12 V DC.

  1. 01Minimum inverter = 500 x 2 = 1000 W
  2. 02DC current = 500 / (12 x 0.9) = 46.3 A
  3. 03DC power = 500 / 0.9 = 556 W

Domande Frequenti

Pure sine vs modified sine?

Pure sine wave is needed for sensitive electronics, motors, and medical equipment. Modified sine is cheaper but can cause noise and overheating.

Why account for surge?

Motors, compressors, and power tools draw 2-3x rated current at startup. The inverter must handle this briefly.

What wire gauge for DC input?

At 500 W on 12 V the DC current is ~46 A. Use at minimum 4 AWG copper wire for short runs.

Impara

Ohm's Law Guide

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