Escape Velocity Calculator
Calculate the minimum velocity needed to escape a gravitational field using v = sqrt(2 * G * M / r).
Velocidad de Escape
11,185.98 m/s
Escape Velocity vs Mass of Celestial Body
Fórmula
## Escape Velocity Escape velocity is the minimum speed an object must have to permanently leave a gravitational field without further propulsion. ### Derivation from Energy Conservation Setting kinetic energy equal to gravitational potential energy: **(1/2)mv² = GMm/r** Solving for v: **v = sqrt(2GM/r)** Note that escape velocity is independent of the escaping object's mass.
Ejemplo Resuelto
Escape velocity from Earth's surface.
- 01v = sqrt(2 * G * M / r)
- 02v = sqrt(2 * 6.6743e-11 * 5.972e24 / 6.371e6)
- 03v = sqrt(1.251e8)
- 04v ≈ 11,186 m/s ≈ 40,270 km/h
Preguntas Frecuentes
Does escape velocity depend on the object's mass?
No. Escape velocity depends only on the mass and radius of the body being escaped from, not on the mass of the escaping object.
What is Earth's escape velocity?
Approximately 11,186 m/s or about 40,270 km/h from Earth's surface.
Does direction matter for escape velocity?
The magnitude is the same regardless of direction (as long as the path doesn't intersect the body). However, launching parallel to the surface requires slightly more energy due to the need to also gain altitude.
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