Blackbody Peak Wavelength Calculator
Find the peak emission wavelength of a blackbody using Wien's displacement law: lambda_max = b / T, where b = 2.898e-3 m K.
Longitud de Onda Pico
0.000000501558 m
Peak Wavelength vs Temperature
Fórmula
## Wien's Displacement Law The wavelength at which a blackbody emits most intensely is inversely proportional to its temperature. ### Formula **lambda_max = b / T** - *b* = 2.898 x 10^-3 m K (Wien displacement constant) - *T* = temperature in kelvin Hotter objects peak at shorter (bluer) wavelengths; cooler objects peak at longer (redder) wavelengths.
Ejemplo Resuelto
The Sun's surface at 5778 K.
- 01lambda_max = b / T
- 02lambda_max = 2.898e-3 / 5778
- 03lambda_max = 5.015e-7 m = 501.5 nm
- 04This falls in the green part of the visible spectrum.
Preguntas Frecuentes
Why does the Sun appear yellow-white if it peaks in green?
The Sun emits across the entire visible spectrum. Our eyes perceive the broad combination as white or slightly yellow, not green.
What does a room-temperature object emit?
At 300 K, the peak is at about 9.66 micrometres, in the mid-infrared. This is why thermal cameras work in the infrared.
Is this law exact?
Wien's law gives the peak of the Planck spectrum as a function of wavelength. The peak in frequency differs slightly because the Planck function has different shapes in wavelength vs. frequency space.
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