Kostenloser Blackbody Peak Wellenlänge Rechner
Berechnen Sie den peak wavelength of a blackbody aus its temperature unter Verwendung von Wien\
Spitzenwellenlänge
0.000000501558 m
Peak Wavelength vs Temperature
Formel
Wien's Displacement Law
The wavelength at which a blackbody emits most intensely is inversely proportional to its temperature.
Formula
lambda_max = b / T
Hotter objects peak at shorter (bluer) wavelengths; cooler objects peak at longer (redder) wavelengths.
Lösungsbeispiel
The Sun's surface at 5778 K.
- 01lambda_max = b / T
- 02lambda_max = 2.898e-3 / 5778
- 03lambda_max = 5.015e-7 m = 501.5 nm
- 04This falls in the green part of the visible spectrum.
Häufig Gestellte Fragen
Why does the Sun appear yellow-white if it peaks in green?
The Sun emits across the entire visible spectrum. Our eyes perceive the broad combination as white or slightly yellow, not green.
What does a room-temperature object emit?
At 300 K, the peak is at about 9.66 micrometres, in the mid-infrared. This is why thermal cameras work in the infrared.
Is this law exact?
Wien's law gives the peak of the Planck spectrum as a function of wavelength. The peak in frequency differs slightly because the Planck function has different shapes in wavelength vs. frequency space.
Lernen