Leistung Factor Correction Rechner
Berechnen Sie capacitor bank size for power factor correction. Reduce reactive power charges und line losses.
Required Capacitor Bank
55.3 kVAR
Required Capacitor Bank vs Real Power
Formel
## Power Factor Correction Low power factor means the utility must deliver more current (and apparent power) than the load actually uses. Capacitor banks supply reactive power locally. ### Formula **kVAR needed = kW x (tan(arccos(PF_current)) - tan(arccos(PF_target)))** ### Benefits - Reduced utility power factor penalties - Lower line current (smaller cables, less loss) - Freed transformer and distribution capacity Most utilities penalize power factors below 0.90. Correcting to 0.95 is a common economic target.
Lösungsbeispiel
100 kW load at PF 0.75, correcting to PF 0.95.
- 01Current angle: arccos(0.75) = 41.41 degrees, tan = 0.8819
- 02Target angle: arccos(0.95) = 18.19 degrees, tan = 0.3287
- 03kVAR needed: 100 x (0.8819 - 0.3287) = 55.3 kVAR
- 04kVA reduction: 100/0.75 - 100/0.95 = 133.3 - 105.3 = 28.1 kVA
Häufig Gestellte Fragen
What causes low power factor?
Inductive loads like motors, transformers, and fluorescent lighting draw reactive current that lags voltage, reducing power factor.
Can I overcorrect power factor?
Yes. A leading power factor (above 1.0 correction) can cause voltage rise and resonance. Do not exceed PF 0.98-0.99.
Where should capacitors be installed?
At the load for maximum benefit, at the main bus for simplicity, or a combination. Automatic switching banks handle varying loads.
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