Inverter Sizing Rechner
Berechnen Sie den right inverter size for your AC loads including surge requirements und DC input current.
Minimum Inverter Rating
1,000 W
Minimum Inverter Rating vs Continuous Load
Formel
## Inverter Sizing ### Formulas **Inverter Rating = Continuous Load x Surge Multiplier** **DC Current = AC Load / (DC Voltage x Efficiency)** Motors and compressors draw 2-3x surge at startup. Size the inverter for the surge, not just continuous load.
Lösungsbeispiel
500 W continuous load, 2x surge, 90% efficient inverter on 12 V DC.
- 01Minimum inverter = 500 x 2 = 1000 W
- 02DC current = 500 / (12 x 0.9) = 46.3 A
- 03DC power = 500 / 0.9 = 556 W
Häufig Gestellte Fragen
Pure sine vs modified sine?
Pure sine wave is needed for sensitive electronics, motors, and medical equipment. Modified sine is cheaper but can cause noise and overheating.
Why account for surge?
Motors, compressors, and power tools draw 2-3x rated current at startup. The inverter must handle this briefly.
What wire gauge for DC input?
At 500 W on 12 V the DC current is ~46 A. Use at minimum 4 AWG copper wire for short runs.
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