Kepler\ — Formel
## Kepler's Third Law
For bodies orbiting the same central mass, the square of the period is proportional to the cube of the semi-major axis.
### Simplified Form (Solar System)
**T² = a³** when T is in Earth years and a is in AU.
Rearranging: **a = T^(2/3)**
For bodies orbiting the same central mass, the square of the period is proportional to the cube of the semi-major axis.
### Simplified Form (Solar System)
**T² = a³** when T is in Earth years and a is in AU.
Rearranging: **a = T^(2/3)**
Lösungsbeispiel
Mars has an orbital period of 1.881 years. Find its semi-major axis.
- a = T^(2/3)
- T² = 1.881² = 3.538
- a = 3.538^(1/3) = 1.524 AU
- In km: 1.524 × 149 597 870.7 ≈ 228 million km