Calcolatrice Calore di Vaporizzazione Gratuita
Calcola l'energia necessaria per la vaporizzazione di una sostanza.
Heat Energy Required
2,260,000 J
Heat Energy Required vs Mass
Formula
## Heat of Vaporization The heat of vaporization is the energy needed to convert a liquid to gas at constant temperature. ### Formula **Q = m * L_v** For water, L_v = 2,260,000 J/kg = 2260 kJ/kg, much larger than the heat of fusion because more energy is needed to fully separate molecules.
Esempio Risolto
Boiling 1 kg of water at 100°C.
- 01Q = m * Lv
- 02Q = 1 * 2260000
- 03Q = 2,260,000 J = 2260 kJ
Domande Frequenti
Why is the heat of vaporization so much larger than fusion?
Vaporization requires completely separating molecules from each other against all intermolecular forces, while melting only loosens the crystal structure.
Why does sweating cool you down?
Evaporating sweat absorbs a large amount of heat from your skin (the latent heat of vaporization), effectively cooling the body.
Does boiling point depend on pressure?
Yes. Lower pressure lowers the boiling point. This is why water boils at a lower temperature at high altitudes.
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