कक्षीय वेग कैलकुलेटरसूत्र

Orbital Velocity

For a circular orbit, gravitational force provides the centripetal force.

Derivation

Setting G*M*m/r² = m*v²/r and solving:

v = sqrt(G * M / r)

The orbital period is T = 2*pi*r / v.

हल किया गया उदाहरण

Low Earth orbit at 400 km altitude (r = 6,371 + 400 = 6,771 km).

  1. v = sqrt(G * M / r)
  2. v = sqrt(6.6743e-11 * 5.972e24 / 6.771e6)
  3. v = sqrt(5.888e7)
  4. v ≈ 7,674 m/s
  5. T = 2*pi*r / v ≈ 5,541 s ≈ 92.3 minutes