De Broglie Wavelength Calculator
Calculate the de Broglie wavelength of a particle from its momentum: lambda = h / (m * v), where h is Planck's constant.
De Broglie Wavelength
0.000000000727412 m
सूत्र
## De Broglie Wavelength Louis de Broglie proposed that all matter has wave-like properties, with a wavelength inversely proportional to momentum. ### Formula **lambda = h / p = h / (m v)** - *h* = 6.626 x 10^-34 J s (Planck constant) - *m* = particle mass - *v* = particle velocity This wavelength is measurable for electrons and neutrons, and is the basis of electron microscopy.
हल किया गया उदाहरण
Electron (m = 9.109e-31 kg) at v = 1e6 m/s.
- 01lambda = h / (m v)
- 02p = 9.109e-31 * 1e6 = 9.109e-25 kg m/s
- 03lambda = 6.626e-34 / 9.109e-25
- 04lambda = 7.274e-10 m = 0.727 nm
अक्सर पूछे जाने वाले प्रश्न
Can macroscopic objects have a de Broglie wavelength?
Technically yes, but it is negligibly small. A 1 kg ball at 1 m/s has a wavelength of about 6.6 x 10^-34 m, far too tiny to ever detect.
How is the de Broglie wavelength measured?
By diffraction experiments. Electrons scattered off crystal lattices produce interference patterns consistent with their predicted wavelength.
Why is this important for electron microscopes?
Electron wavelengths at high energies are much shorter than visible light, allowing electron microscopes to resolve atomic-scale features.
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