बर्नूली समीकरण कैलकुलेटरसूत्र

## Bernoulli's Equation

For steady, incompressible, frictionless flow along a streamline, the total energy per unit volume remains constant.

### Formula

**P1 + 0.5 rho V1^2 + rho g z1 = P2 + 0.5 rho V2^2 + rho g z2**

Rearranging for P2:

**P2 = P1 + 0.5 rho (V1^2 - V2^2) + rho g (z1 - z2)**

This equation is the foundation of fluid mechanics, connecting pressure, velocity, and elevation energy.

हल किया गया उदाहरण

Water (1000 kg/m^3) flows from point 1 (P1=200 kPa, V1=2 m/s, z1=5 m) to point 2 (V2=5 m/s, z2=0 m).

  1. Velocity term: 0.5 x 1000 x (4 - 25) = -10,500 Pa
  2. Elevation term: 1000 x 9.81 x (5 - 0) = 49,050 Pa
  3. P2 = 200,000 - 10,500 + 49,050 = 238,550 Pa = 238.55 kPa