Blackbody Peak Wavelength Calculator

Find the peak emission wavelength of a blackbody using Wien's displacement law: lambda_max = b / T, where b = 2.898e-3 m K.

K

Peak Wavelength

0.000000501558 m

Peak Wavelength (nm)501.56 nm
Peak Frequency597,737,888,198,757.80 Hz

Peak Wavelength vs Temperature

Voir la formule →

Formule

## Wien's Displacement Law The wavelength at which a blackbody emits most intensely is inversely proportional to its temperature. ### Formula **lambda_max = b / T** - *b* = 2.898 x 10^-3 m K (Wien displacement constant) - *T* = temperature in kelvin Hotter objects peak at shorter (bluer) wavelengths; cooler objects peak at longer (redder) wavelengths.

Exemple Résolu

The Sun's surface at 5778 K.

  1. 01lambda_max = b / T
  2. 02lambda_max = 2.898e-3 / 5778
  3. 03lambda_max = 5.015e-7 m = 501.5 nm
  4. 04This falls in the green part of the visible spectrum.