Calculateur de Courant de Court-Circuit
Calculez le courant de court-circuit dans une installation électrique.
Required Capacitor Bank
55.3 kVAR
Required Capacitor Bank vs Real Power
Formule
Power Factor Correction
Low power factor means the utility must deliver more current (and apparent power) than the load actually uses. Capacitor banks supply reactive power locally.
Formula
kVAR needed = kW x (tan(arccos(PF_current)) - tan(arccos(PF_target)))
Benefits
Most utilities penalize power factors below 0.90. Correcting to 0.95 is a common economic target.
Exemple Résolu
100 kW load at PF 0.75, correcting to PF 0.95.
- 01Current angle: arccos(0.75) = 41.41 degrees, tan = 0.8819
- 02Target angle: arccos(0.95) = 18.19 degrees, tan = 0.3287
- 03kVAR needed: 100 x (0.8819 - 0.3287) = 55.3 kVAR
- 04kVA reduction: 100/0.75 - 100/0.95 = 133.3 - 105.3 = 28.1 kVA
Questions Fréquentes
What causes low power factor?
Inductive loads like motors, transformers, and fluorescent lighting draw reactive current that lags voltage, reducing power factor.
Can I overcorrect power factor?
Yes. A leading power factor (above 1.0 correction) can cause voltage rise and resonance. Do not exceed PF 0.98-0.99.
Where should capacitors be installed?
At the load for maximum benefit, at the main bus for simplicity, or a combination. Automatic switching banks handle varying loads.
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