Neutralization Calculator Formula

Understand the math behind the neutralization calculator. Each variable explained with a worked example.

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Formulas Used

Volume of Base Needed

vol_base = (conc_acid * vol_acid) / conc_base

Moles Neutralized

moles_neutralized = conc_acid * vol_acid / 1000

Variables

VariableDescriptionDefault
conc_acidAcid Concentration(M)0.1
vol_acidAcid Volume(mL)50
conc_baseBase Concentration(M)0.1

How It Works

How to Calculate Neutralization Volume

Formula

V_b = (C_a × V_a) / C_b

Where:

  • V_b = volume of base required (mL)
  • C_a = concentration of acid (M)
  • V_a = volume of acid (mL)
  • C_b = concentration of base (M)

    • This applies to monoprotic 1:1 neutralization. For polyprotic acids, multiply by the number of acidic protons.

    Worked Example

    Neutralize 50 mL of 0.1 M HCl with 0.1 M NaOH.

    conc_acid = 0.1vol_acid = 50conc_base = 0.1
    1. 01V_b = (C_a × V_a) / C_b
    2. 02V_b = (0.1 × 50) / 0.1
    3. 03V_b = 5 / 0.1
    4. 04V_b = 50 mL

    Frequently Asked Questions

    What is neutralization?

    Neutralization is a reaction between an acid and a base that produces water and a salt. For strong acids and bases, the reaction goes to completion.

    Is neutralization always exothermic?

    Yes, strong acid-strong base neutralization releases about 57.1 kJ/mol of water formed. Weak acid or base reactions release less due to partial dissociation.

    What happens if I add excess base?

    The solution becomes basic (pH > 7). The excess hydroxide ions remain in solution.

    Ready to run the numbers?

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