Free Heat of Vaporization Calculator
Calculate energy required to boil a substance using Q = m * Lv.
kg
J/kg
Heat Energy Required
2,260,000 J
Heat Energy (kJ)2,260.00 kJ
Heat Energy Required vs Mass
Heat of Vaporization
The heat of vaporization is the energy needed to convert a liquid to gas at constant temperature.
Formula
Q = m * L_v
For water, L_v = 2,260,000 J/kg = 2260 kJ/kg, much larger than the heat of fusion because more energy is needed to fully separate molecules.
Example Calculation
Boiling 1 kg of water at 100°C.
- 01Q = m * Lv
- 02Q = 1 * 2260000
- 03Q = 2,260,000 J = 2260 kJ
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