开关稳压器效率计算器
计算开关稳压器的转换效率。
Minimum Inverter Rating
1,000 W
Minimum Inverter Rating vs Continuous Load
公式
## Inverter Sizing ### Formulas **Inverter Rating = Continuous Load x Surge Multiplier** **DC Current = AC Load / (DC Voltage x Efficiency)** Motors and compressors draw 2-3x surge at startup. Size the inverter for the surge, not just continuous load.
计算示例
500 W continuous load, 2x surge, 90% efficient inverter on 12 V DC.
- 01Minimum inverter = 500 x 2 = 1000 W
- 02DC current = 500 / (12 x 0.9) = 46.3 A
- 03DC power = 500 / 0.9 = 556 W
常见问题
Pure sine vs modified sine?
Pure sine wave is needed for sensitive electronics, motors, and medical equipment. Modified sine is cheaper but can cause noise and overheating.
Why account for surge?
Motors, compressors, and power tools draw 2-3x rated current at startup. The inverter must handle this briefly.
What wire gauge for DC input?
At 500 W on 12 V the DC current is ~46 A. Use at minimum 4 AWG copper wire for short runs.
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