串联电路计算器
计算串联电路的总电阻、电流和电压分配。
A
Ω
Ω
Current through R1
0.6667 A
Current through R20.3333 A
Current through R1 vs Total Current
公式
## Current Divider Rule When two resistors are in parallel, current splits inversely proportional to resistance. ### Formula **I1 = I_total x R2 / (R1 + R2)** **I2 = I_total x R1 / (R1 + R2)** More current flows through the smaller resistance.
计算示例
1 A splits between R1 = 100 ohms and R2 = 200 ohms in parallel.
- 01I1 = 1 x 200 / (100 + 200) = 0.6667 A
- 02I2 = 1 x 100 / (100 + 200) = 0.3333 A
- 03Check: 0.6667 + 0.3333 = 1.0 A
常见问题
Why does the smaller resistor carry more current?
Lower resistance offers an easier path so more current flows through it.
Does this work for more than two resistors?
Yes, but the formula extends. For two resistors the simplified form here is most convenient.
What if R1 equals R2?
Current divides equally: each branch carries half the total.
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